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J.D. Drew Net Worth

J.D. Drew Net Worth

Net Worth: Under Review

  • Source of Wealth Major League Baseball, Sports
  • Height 6' 1" (1.85 m)
  • Marital Status Married (Sheigh Drew)
  • Full Name David Jonathan "J. D." Drew
  • Nationality United States
  • Date of Birth November 20, 1975
  • Ethnicity Caucasian
  • Weight 194 lbs (88 kg)
  • Occupation Baseball Player
  • Education Florida State University
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About J.D. Drew

J.D. Drew is a retired baseball player who previously played in the Major League Baseball league.

David Jonathan “J. D.” Drew was born on November 20, 1975 in Valdosta, Georgia. While attending Florida State University, he became a recipient of several awards, including the Golden Spikes Award, the Dick Howser Trophy, the Collegiate Baseball Player of the Year, Sporting News Player of the Year, as well as the ACC Player of the Year in 1997.

In the same year, he was selected by the Philadelphia Phillies as its second overall pick in the MLB Draft. Drew and his agent, Scott Boras insisted that the former would not sign for the Phillies for a contract less than $10 million. Nevertheless, Drew was still drafted by the Phillies. Eventually, he ended up playing in the independent Northern League for the St. Paul Saints.

After a short stint with the St.Paul Saints, Drew was signed by the St. Louis Cardinals to a $7 million contract. After a while, he was traded to the Atlanta Braves. In 2004, he was signed by Los Angeles to a five-year, $55 million contract. By January 2007, he was again signed by the Boston Red Sox to a five-year, $70 million deal.